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The average set of seven consecutive integers is (x + 1) and that of a different set of seven consecutive integers is (x – 1). Find the average of all the integers in both the sets considering each of the common integers only once.
x
x + 2
(x – 1)/2
x + 1
In AP series, If the number of terms are odd, then middle number is the average of the series.
So Assume 'x+1' to be a number 7 => x+1 = 7 ; x = 6
Hence 'x -1' will become 5
Since 'x+1' and 'x-1' are the averages; So Let's make the two series having these averages.
4 5 6 7 8 9 10 (Average is highlighted)
And
2 3 4 5 6 7 8 9 (Average is highlighted)
Let's identify the non repetitive number of these 2 series.
2 3 4 5 6 7 8 9 10
Required Average = Sum of the Above Terms/9 = 54/9 = 6 (Here 6 stands for 'x')
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