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A can complete the work in 60% less time than B. Beginning with the second day, the amount of work which can they do keeps of doubling. If in this way they can complete the work together in 2 days, then in how many days they can complete the work if their efficiencies remain constant?
2.5 days
3.5 days
4 days
3 days
Explanation: Days of A : B = 40 : 100 = 2 : 5 Days in which A can complete work = 2x, and B = 5x They complete the work in 2 days with their efficiencies doubling the second day. So (1/2x + 1/5x) + (1/4x + 1/10x) = 1/2 Solve, x = 21/10 days So A does work in 2 * 21/10 days = 21/5 days and B in 5 * 21/10 = 21/2 days So together: 5/21 + 2/21 = 7/21 = 1/3 work in 1 day or whole work in 3 days
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