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A, B and C are three friends that take 20 days to finish a work. The time taken by B is twice the time taken by A and C together and time taken by C to do the work is thrice the time taken by A and B together. How much time will be taken by A alone to do the work.
42 days
44 days
46 days
48 days
1/a + 1/b + 1/c = 1/20 (given) In first case let time taken by A and C together is p days, then the time taken by B will be 2p. Substitute in the above equation and we get p = 60 (time taken by B to complete the work). Similarly in the second case, u will get P = 80 (time taken by C to complete the work) Now, 1/a = 1/20 – 1/60 – 1/80 to get the answer = 48 days
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