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Directions: Read the given instructions and answer the following questions:
Four boxes A, B, C and D are placed one above the other. One box is placed between A and C. A is adjacent to D.
If P is added to this stack, above C below A and Q is placed just above D. All boxes contain different number of pencils in consecutive multiple of 6 from bottom to top. A contains 30 pencils. B is not placed at the top.
Which box is placed at the top?
A
P
B
Q
D
- The boxes are A, B, C, D, P, and Q, arranged one above the other.
- A is placed just adjacent to D and contains 30 pencils.
- Since A and C have one box between them, and A is adjacent to D, A must be either at the 2nd or 3rd position.
- If A is second, D is at the bottom. That makes C be 4th and P at the 3rd position.
- Q is placed just above D. If D is at the bottom, Q is right above D.
- B is not at the top. Therefore, we can place B at the position of P.
- Given the sequence of pencils, positions are 6, 12, 18, 24, 30, 36 pencils respectively ascending.
- As per pencil distribution, P will have 36 pencils being top, and C would be the 6-pencil box.
- Hence, the topmost box becomes apparent as P.
So, based on the given instructions, your answer is incorrect. The top box must be: Option: 2, P
.
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