Multiple Choice Questions on It is known that 15 10 and 5 of males in division A C and F respectively are married while 10 and 20........... for SBI(PO) Exam Preparation

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Multiple Choice Questions

It is known that 15 10 and 5 of males in division A C and F respectively are married while 10 and 20...........

Quantitative Aptitude (SBI-PO) Percentage
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    Directions : Study the following pie charts carefully and answer the questions given beside.
     

    Number of soldiers in army of a country is 10,00,000. Total females in the army are 2,80,000. There are 6 divisions within the army namely A, B, C, D, E and F. In the meeting of Defence Minister with Chief of Army staff, number of soldier and their status within each division in terms of male and female population were discussed. Chief of Army Staff gave the following pie charts to Defence Minister.
     
    Population of each division in terms of percentage has been given in pie chart-1, and pie chart-2 gives the number of males in those divisions in terms of degrees within pie chart of total male population in the army.

    It is known that 15%, 10% and 5% of males in division A, C, and F respectively are married, while 10% and 20 % from B and D respectively are married. In B and D how many more/less men are married with respect to A, C, and F?

    5%

    Incorrect Answer

    5.25%

    Incorrect Answer

    6%

    Incorrect Answer

    6.25%

    Correct Answer

    None of these

    Incorrect Answer
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    Explanation:
    From the common explanation, we have
     
    Males in A = 80,000, 15% are married, thus 15% of 80,000
    = 15/100 × 80,000 = 12,000
    Males in C = 1,10,000, 10% are married, thus 10% of 1,10,000
    = 10/100 × 1,10,000 = 11,000
    Males in F = 1,80,000, 5% are married, thus 5% of 1,80,000
    = 5/100 × 1,80,000 = 9,000
    Total married male in A, C and F = 12,000 + 11,000 + 9,000 = 32,000
    Males in B = 1,20,000, 10% are married, thus 10% of 1,20,000
    = 12/100 × 1,20,000 = 12,000
    Males in D = 90,000, 20% are married, thus 20% of 90,000
    = 20/100 × 90,000 = 18,000
    Total married male in B and D = 12,000 + 18,000 = 30,000
    Difference = 32,000 – 30,000 = 2,000
    In B and D how many more/less men are married with respect to A, C, and F
    = 2000/32000 × 100 = 6.25%
     
    Hence, option D is correct.

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