Sun	Mon	Tue	Wed	Thu	Fri	Sat
23	24	25	26	27	28	1
2	3	4	5	6	7	8
9	10	11	12	13	14	15
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23	24	25	26	27	28	29
30	31	1	2	3	4	5

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Multiple Choice Questions

Due to fever Tipu did not joined the work but Ismail took his place who can complete the w...........

Quantitative Aptitude (SBI-PO) Time and work

Direction: Study the following Table and answer the questions that follow:

Due to fever Tipu did not joined the work but Ismail took his place , who can complete the work in 25 days. He did Tipu’s part of work. After that khachara joined the work but worked for same number of days as Ismail. If remaining work was completed by Bagha who is 300% more efficient than Lakha then in how many days was the whole work completed?

63/2

25/13

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Explanation:

Explanation – Ismail completes work in = 25 days
Kachara completes work in = 20 days
Bagha is 300% more efficient than Lakha, so we can find that in how many days Bagha can complete this work.
(100 + 300)% of Bagha = Lakha
from the table we can calculate that Lakha can complete the whole work in 32 days
400% of Bagha = 32 ( number of days in which Lakha can complete the work)
Bagha = (32/400) × 100
= 8 days
Total work = LCM ( Ismail, Kachara and Bagha)
= LCM ( 25, 20 , 8)
= 200 unit
Now we can find efficiency of each persons.
Ismail = 8 unit
Kachara = 10 unit
Bagha = 25 unit
Ismail did only 25% of total work i.e. 50 unit
No. of days Ismail took to complete 25% work = 50 / 8
= 25/4 days
No. of days Kachara works = 25/4 days ( said in question)
Work done by Kachara = 10 × (25/4)
= 125/2 unit
Remaining work = 200 – ( 50 + 125/2)
= 175 / 2 unit
Remaining work done by Bagha
= (175/2) / 25
= 175/50
= 7/2 days
Total work completes in = (25/4) + (25/4) + (7/2)
= 32/2
= 16 days