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Tips and Tracks for profit and Loss
Profit and loss are the terms related to monetary transactions in trade and business. Whenever a purchased article is sold, then either profit is earned or loss is incurred.
Cost Price (CP) This is the price at which an article is purchased or manufactured.
Selling Price (SP) This is the price at which an article is sold.
Overhead Charges Such charges are the extra expenditures on purchased goods apart from actual cost price.
Such charges include freight charges, rent, salary of employees, repairing cost on purchased articles etc.
Note: If overhead charges are not specified in the question, then they are not considered
Profit (SP>CP) When an article is sold at a price more than its cost price, then profit is earned,
Loss (CP>SP) When an article is sold at a price lower than its cost price, then loss is incurred.
Question: 1 A man buys an article for Rs. 300 and sells it for Rs. 900. Find profit/loss.
Solution. Here, SP > CP Profit is earned. According to the formula, Profit = SP - CP = 900 - 300 = Rs. 600
Question: 2 Raman purchased a car for Rs. 5 lakh and sold it for Rs 4 lakh. Find profit/loss in this transaction.
Solution. Here, SP < CP Loss is incurred in this case. According to the formula, Loss= CP- SP= (5-4) lakh=Rs. l lakh
Profit and Loss Tricks
As you have learned until now how to calculate profit as well as loss and also the percentage of them. Now let us learn some tricks or formulas to solve maths problems based on gain and loss, starting from the general formulas.
Type:1(Find Profit/Loss%)
Question:3 A person buys a toy for Rs. 50 and sells it for Rs.75. What will be his gain percent ? Solution. Given,CP=Rs. 50 and SP=Rs.75 Profit = SP -CP = 75 - 50 = Rs. 25 According to the formula, P% = (P/CP) x 100 P%=25/50 x 100=50%
Question:4 A person buys a cycle for RS. 550 but because of certain urgency,he sells it for RS. 450. Find his loss percent.
Solution. Given, CP = RS. 550 and SP = RS. 450 Loss = CP-SP = 550 - 450 = RS.100 According to the formula, L oss % = Loss/ CP*100% = 100/550*100 = 18.18 %
Type:2(Find SP,CP)
Question:5 Find the SP, when CP is Rs 80 and gain is 20%.
Solution: CP = Rs. 80, Gain percent = Rs. 20% SP=120% of 80 SP=120/100 x 80 Thus SP is Rs. 96.
Question:6 A man sold a fan for Rs. 465. Find the cost price if he incurred a loss of 7%.
Solution: CP = [100 / (100 – Loss %)] * SP Therefore, the cost price of the fan = (100/93)*465 = Rs. 500
Type:3
If A sold an article to B at a profit (loss) of r1 % and B sold this article to C at a profit (loss) of r2%,then
Cost price of article for C is given by cost Price for
Question:7 Nikunj sold a machine to Sonia at a profit of 30%. Sonia sold this machine to Anu at a loss of 20%. If Nikunj paid Rs 5000 for this machine, then find the cost price of machine for Anu.
Solution:1 Nikunj to sonia at 20% profit cp for nikunj= 5000
Sp for nikunj=cp of sonia
sp=30/100×5000+5000. (30% profit)
= 6500
Sonia to Anu
cp for Sonia= 6500
sp for sonia=cp of Anu
sp=6500-20/100×6500. (20% loss)
=Rs. 5200
Hence,cost price of machiene for Anu is Rs. 5200
Solution 2: CP for Anu= 5000x 130/100 x80/100=5200
Hence,cost price of machiene for Anu is 5200
OR by ratio method 10 : 13 ( 30 % profit ) 5 : 4 ( 20 % loss) ---------- 50 : 52 ----------- 50 unit = 5000 1 unit = 100 52 unit = 5200
Type:4 By selling an item for Rs. x, a man losses L%. If he want to gain G% then Selling Price will be=x(100+P)/100-L
Question:8 By selling a watch for Rs. 1440, a man losses 10%. At what price should he sell it to gain 5% ? Solution 1: Selling price of watch is S.P.=Rs.1440
Cost price of watch = 100−loss% / 100 ×S.P
∴ Cost price of watch =(100−10)/100×1440
∴ Cost price of watch =90/100×1440=Rs.1600
Selling price of watch to gain 5%=1600×1005+1600=80+1600=Rs.1680
Solution 2:
Sp= 1440x105/90=1680 Selling price of watch =Rs 1680
or
if an article is sold at 10 % loss then it was sold at 90% of its value 90% of c.p = 1440 1% of c.p = 1440/90 1% of c.p = 16 Now , if we want a profit of 5% i.e we have to sold the article at 105 % 16 x 105 = 1680 rs . Type:5
If cost price of 'a' articles is equal to the selling price of 'b' articles, then
Profit %=
If it positive then profit otherwise loss
Question:9 The cp of 21 articles is equal to sp of 18 articles. find gain or loss %
Solution1: CP of 21 articles=x
CP of 1 article=x/21
SP of 18 articles=x
SP of 1 article=x/18
since x/21
gain=SP-CP
=x/18-x/21
=(7x-6x)/126
=x/126
gain%=gain/CP×100
=(x/126÷x/21)×100
=(x/126×21/x)×100
=100/6
=50/3
=16 2/3%
Solution 2: Profit %=
=(21-18)/18 x 100
=1/6 x 100= 16 2/3%
OR
21 c.p = 18 s.p c.p/s.p = 18/21 it means c.p : s.p = 6:7 % profit = 1/6 x 100% = 16 2/3 % or 16.66 %
Type:6 : PROFIT = SELLING PRICE - COST PRICE LOSS = COST PRICE - SELLING PRICE
Question:10 After selling 72 articles a man losses SP of 9 articles. Find loss % ?
Solution: Let the S.P of one article = RS 1
S.P of 72 articles=72*1=72
Loss=9
C.P=72+9=81
Loss% = loss/CP x 100
= 9/81 x 100=11 1/9 % OR loss = c.p - s.p 9 s.p = 72 ( cp - s.p ) 9 s.p = 72 c.p - 72 s.p
i.e -----72 c.p = 81 s.p c.p / s.p = 9 / 8 loss = (1/9) x 100 % 11 1/9 %
Question:11 After selling 72 articles a man earns a profit of SP of 9 articles. Find profit%.
Solution : Let the S.P of one article = RS 1
Profit=9
C.P=72-9=63
Profit % = Profit/CP x 100
= 9/63 x 100=14 2/7 % OR profit = s.p - c.p 9 s.p = 72 ( s.p - c.p )
9 s.p = 72 s.p - 72 c.p or 72 c.p = 63 s.p c.p : s.p = 7 : 8 profit % = (1/7) x 100% = 14 2/7 %
Type:7
If a person sells two similar articles, one at a gain of a% and another at a loss of a%, then the seller always incurrs a loss which is given by
loss= a2/100 %
Question 12: A man sold 2 flats for Rs 675958 each.on one he gains 30% while on the other he losses 30%. How much does he gain/loss % in the whole transaction?
Solution: Loss%=30 x 30/100=9%
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