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The HCF of two numbers, each having three digits, is 17 and their LCM is 714. Find the sum of the numbers.
289
391
221
731
Let two numbers be 17x and 17y respectively, as 17 is the HCF of these numbers.
Now, LCM of 17x and 17y is 17xy and, according to the question LCM of these two numbers = 714 ⇒17xy=714 ⇒xy=714/17 ⇒xy=42=7×6 Now we have two possible scenarios,
either, x=7 and y=6 ----(1)
or, x=6 and y=7 ----(2)
In the first scenario, where x=7 and y=6, numbers will be,
17x=17×7=119 17y=17×6=102. Or, in the second case where x=6 and y=7, numbers will be 102 and 119.
Required sum would be,
=102+119
= 221
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