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Abhishek can do a piece of work in 10 days, Babita can do it in 20 days. With the help of Harilal, they finish the work in 4 days. In how many days Harilal alone can do the whole work?
7days
6days
4days
5days
Efficiency of Abhishek = 10% Efficiency of Babita = 5% Efficiency of Abhishek, Babita and Harilal = 25% Efficiency of Harilal = (efficiency of Abhishek,Babita and Harilal)-(efficiency of Abhishek and Babita) = (40)-(10+5) = 25% Number of days required by Harilal to work alone = 100/25 = 4 days
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