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A work when done by 10 women is completed in 12 days. The same work can be completed in 8 days when done by 5 men. How many days will it take to complete when 6 women and 3 men are employed to perform the same job?
12
10
8
5
10W * 12 = 8 * 5M , M = 3W
Let total days required to complete the complete work by 6 women and 3 men be ‘y’.
(6W+3M) y = 10W*12
(10W*12 is equal to the total work)
(6W+9W) y = 10W *12
15Wy = 10W *12
Y = 8 days
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