Multiple Choice Questions

Sita and Geeta start at same the time to ride from place A to place B which is 90 km away from place...........

Quantitative Aptitude (MTS) Time & distance

Sita and Geeta start at same the time to ride from place A to place B, which is 90 km away from place A. Sita travels 3 km per

hour slower than Geeta. Geeta reaches place B and at once turn back, meeting Sita 15 km from place B. Geeta's speed (in

km/h) is:

This questions was previously asked in

SSC MTS 14th October 2021 Shift-1

7.5

10.5

- Sita and Geeta start traveling from place A to place B.

- The distance from A to B is 90 km.

- Geeta's speed is 3 km/h faster than Sita's.

- Geeta reaches place B and starts back, meeting Sita 15 km from place B.

- Let Geeta's speed be $x$ km/h.

- Sita's speed is $x - 3$ km/h.

- Geeta travels 90 km to B and 15 km back, totaling 105 km, while Sita travels 75 km when they meet.

- Time taken by both to meet is equal. For Geeta: $\frac{105}{x}$ , for Sita: $\frac{75}{x - 3}$ .

- Equation: $\frac{105}{x} = \frac{75}{x - 3}$ .

Solving:

- $105 (x - 3) = 75 x$

- $105 x - 315 = 75 x$

- $30 x = 315$

- $x = 10.5$

- The correct answer is Option: 4 - 10.5 km/h.

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