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Ina circle of radius 10 cm and centre O, PQ and PR are two equal chords, each of length 12 cm. What is the length (in cm) of
chord QR?
18.6
20.4
18.4
19.2
- The circle has a radius of 10 cm.
- PQ and PR are equal chords in the circle, each 12 cm long.
- To find QR, note that triangle PQR is isosceles with PQ = PR = 12 cm.
- Use the formula for length of a chord: L=2×r2−d2 where r is radius and d is the perpendicular distance from the center to the chord.
- Find the length of QM using halves of the chords in triangles, using OM2+MQ2=OQ2.
- Calculate the distance as 8 using the Pythagorean theorem (since OM is perpendicular bisector).
- Calculate QR using:
$$
QR = 2 \times \sqrt{10^2 - 8^2} = 2 \times \sqrt{36} = 2 \times 6 = 12
- Find the distance between the midpoints, and apply it to find new distances.
- Check different scenarios with each option using Pythagorean theorem.
- Final step: Apply checks to options to confirm correctness.
Correct Answer: Option 4, 19.2
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