Multiple Choice Questions

In a circle of radius 10 cm with centre O PQ and PR are two chords each of length 12 cm PO intersect...........

Quantitative Aptitude (CGL) Geometry

In a circle of radius 10 cm, with centre O. PQ and PR are two chords each of length 12 cm PO intersects chord QR at the points

5. The length of OS is:

This questions was previously asked in

SSC CGL 4 June 2019 Shift-1

2.8 cm

2.5 cm

3.2 cm

3 cm

To find the length of OS in the given circle configuration:

- The circle has a radius of 10 cm and contains chords PQ and PR each 12 cm long.

- Using the power of a point theorem, particularly for points related to circle chords, we can find the length OS.

- Let the point where PO intersects QR be S.

- The power of the point theorem states that PO² = PS * PQ = PS * 12 = PR * 12.

- The formula to deduce the length is PO² - PS² = QR²/4.

- Solving through substitution and algebra results in OS being calculated as 2.8 cm.

` 2.8 cm`

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