send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
A number, when divided by 15 and 18 every time, leaves 3 as a remainder, the least possible number is:
83
103
39
93
- To solve the problem, we need a number that, when divided by both 15 and 18, leaves a remainder of 3.
- First, find the Least Common Multiple (LCM) of 15 and 18. The LCM is 90.
- We're looking for a number of the form 90k + 3, where k is an integer, that is the smallest.
- Evaluating the options:
- Option 1: 83 – 83÷15=5 remainder 8. 83÷18=4 remainder 11.
- Option 2: 103 – 103÷15=6 remainder 13. 103÷18=5 remainder 13.
- Option 3: 39 – 39÷15=2 remainder 9. 39÷18=2 remainder 3.
- Option 4: 93 – 93÷15=6 remainder 3. 93÷18=5 remainder 3.
- Therefore, the smallest number that satisfies the condition is 93.
Report error
Please Wait..
Access to prime resources