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In a circle of radius 5 m, AB and CD are two equal and parallel chords of length 8 m each. What is the distance between the
chords?
5 m
6 m
3 m
8 m
- The radius of the circle is 5 m.
- Chords AB and CD are equal and parallel with lengths of 8 m each.
- Since the chords are equal and parallel, their perpendicular distances from the center are equal.
To find the distance from the center to a chord, use the formula:
h=r2−(l/2)2
where r is the radius and l is the length of the chord.
- For each chord:
- h=52−(8/2)2=25−16=9=3m
- The total distance between the chords is:
- 3m+3m=6m
- The correct option is: Option 2: 6 m
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