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In a triangle ABC, point D lies on AB, and points E and F lie on BC suchthat DF is parallel to AC and DE is parallel to AF. If BE = 4
cm, CF = 3 cm, then find the length (in cm) of EF.
5
3
2
1.5
- The setup involves a triangle ABC where specific points D, E, and F lie on lines AB and BC.
- DF is parallel to AC, and DE is parallel to AF, creating a smaller, similar triangle DEF within ABC.
- This similarity maintains the proportionality of corresponding line segments.
- Given BE = 4 cm and CF = 3 cm, we can find EF using the proportionality property.
- In similar triangles, the ratio of corresponding sides is equal. Since DE || AF and DF || AC, triangle DEF is similar to triangle ABC.
- The ratio of BE to CF can be used to find EF using cross-multiplication since EF corresponds to part of BC.
- Therefore, using the ratio 4:3, EF = 2 cm, maintaining the property's equality.
Option 3: 2 cm is the correct answer.
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