send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
train X travelling at 60 km/h overtakes another train Y, 225 m long, and completely passes it in 72 seconds. If the trains had been
going in opposite directions, they would have passed each other in 18 seconds. The length (in m) of X and the speed (in km/h) of
Y are, respectively:
245 and 54
255 and 40
255 and 36
245 and 45
Time taken to cross in opposite direction = 18 second Speed of train X = 60 km/hr = 60 \frac{5}{18}$$ = 16.66 m/sec Length of train Y = 225 m Let the length of train X be l m and speed of train Y be x m/sec. Total length = (225 + l) m Relative speed when trains run opposite direction = (16.66 + x) m/sec Length = speed x time 225 + l = (16.66 + x) 18 225 + l = 300 + 18x l = 75 + 18x ---(1) Relative speed when trains run opposite direction = (16.66 - x) m/sec 225 + l = (16.66 - x) 72 225 + l = 1200 - 72x l = 975 - 72x ---(2) By eq(1) and (2), 75 + 18x = 975 - 72x 90x = 900 x = 10 m/sec Speed (in km/h) of Y = 10 \frac{18}{5} = 36 km/hr Put the value of x in eq(1) l = 75 + 18 10 = 255 m
Report error
Access to prime resources