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Multiple Choice Questions

An alloy contains 4 parts bronze and 6 parts copper How much part of mixture should be drawn out and...........

Quantitative Aptitude(IBPS CL) Mixture and Alligation

An alloy contains 4 parts bronze and 6 parts copper. How much part of mixture should be drawn out and replaced with bronze so that the ratio of bronze to copper gets reversed in new mixture?

2/5

1/3

1/4

10/3

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Explanation:

Total = 4+ 6 = 10
The old ratio is 4/6 = 2/3, so new ratio of bronze to copper should be 3/2
Let x kg of mixture is drawn out and then x kg of bronze added.
So
Bronze is now = 4 – (4/10)*x + x = 4 + (3x/5)
Copper is now = 6 – (6/10)*x = 6 – (3x/5)
Now [4 + (3x/5)] / [6 – (3x/5)] = 3/2
Solve, x = 10/3
So part of mixture drawn out is (10/3)*10 = 1/3

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