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Multiple Choice Questions

Four among the five are same in a certain way thus form a group Who among the following is odd one o...........

Logical Reasoning(IBPS CL) Puzzle Test

Direction: Read the following information carefully and answer the questions that follow.

Seven people P, Q, R, S, T, U and V. All of them have their birthdays in different months namely January, March, April, May, June, July and August. No two persons share the same birthday month. P's birthday is in January. There are the same number of person having their birthday before and after R. Only one person's birthday is there between S and R. Q's birthday is in the month having 31 days but not in August. There are two person's birthday between Q and V. T's birthday is before U's birthday. Q's birthday is not before R.

Four among the five are same in a certain way thus form a group. Who among the following is odd one out

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Explanation:

- P's birthday is in January.
- R has equal persons' birthdays before and after him, so he is in April.
- S's birthday is one month apart from R, so S is in March.
- Q's birthday is in a 31-day month, not August, could be March, May, July.
- Between Q and V, there are two months.
- T's birthday is before U's.
- Q's birthday isn't before R's, so Q can only be in May or July.

From this:
- P: January
- S: March
- R: April
- Q: May
- V: August
- T and U in June and July, with T before U: T in June, U in July

Analysis of the options:
1. P (January)
2. S (March)
3. R (April)
4. **T (June)** ✅
5. Q (May)

T stands out because all others have birthdays before June.
**YOUR ANSWER IS RIGHT**

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