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A is 1.5 times efficient than B therefore takes 8 days less than B to complete a work. If A and B work on alternate days and A works on first day, then in how many days the work will be completed?
17
19
19.5
21
A=1.5B A/B=3/2(efficiency ratio) A/B=2/3(ratio of day) (3–2)=1=8(according to question) A takes =8×2=16 days B takes=8×3=24 days they together take(1/16+1/24)=5/48 as they work alternate days so (5/48×9)=45/48 therefore 9×2 days=18 daymust take remaining work is (1–45/48)=3/48 as atfirst A start the work so 1/16=1day so 3/48=(16×3/48)=1 day therefore totl days are 18+1=19
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