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Find the least number which when divided by 2, 5, 9 and 12 leaves a remainder 3 but leaves no remainder when same number is divided by 11.
281
357
360
363
LCM(2, 5, 9, 12) = 180 So the number will be somewhat = 180x + 3 This number leaves no remainder when divided by 11, so x = 2 to get (180x+3) fully divided by 11 So number = 180*2 + 3 = 363
Hence, option 4 is the correct answer.
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