Multiple Choice Questions

Suresh and Dinesh travel a distance of 120 km such that the speed of Suresh is more than that of Din...........

Quantitative Aptitude (MTS) Time & distance

Suresh and Dinesh travel a distance of 120 km such that the speed of Suresh is more than that of Dinesh. The sum of their

speeds is 75 km/h, and the total time taken by both is 6 hours and 40 minutes. The speed of Suresh is:

This questions was previously asked in

SSC MTS 22nd October 2021 Shift-2

45 km/h

42 km/h

40 km/h

30 km/h

- Suresh and Dinesh together travel a total of 120 km.

- Their combined speed is 75 km/h.

- The combined time taken is 6 hours and 40 minutes, which is 6.67 hours (since 40 minutes is 2/3 of an hour).

- The total distance should equal the sum of the distances traveled by each, using their respective speeds and times.

- Let's denote Suresh's speed as S km/h and Dinesh's speed as D km/h.

- According to the problem, S + D = 75 km/h.

- The total distance equation is S * T_s + D * T_d = 120 km, where T_s and T_d are the times taken (which sum to 6.67 hours).

- Solving the equations with S > D, we find Suresh's speed is 45 km/h.

Option 1 - 45 km/h is the correct answer.

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