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The average of a, b and c is 8 less than d. If the average of a, b, c and d is 42, then what is the average of(3d - 2) and (d + 5)?
96.5
97.5
99.5
98.5
- Let’s break down the information given:
- The average of a, b, and c is 8 less than d.
- This can be expressed as: (a + b + c)/3 = d - 8.
- The average of a, b, c, and d is 42, so: (a + b + c + d)/4 = 42.
- Solving for the sum of a, b, c, and d gives: a + b + c + d = 168.
- Now, let's find a + b + c using the expressions:
- a + b + c = 3d - 24 (derived from the first equation).
- Combine with the total equation: 3d - 24 + d = 168.
- Solution: 4d = 192 ? d = 48.
- To find the average for (3d - 2) and (d + 5):
- Calculate: 3(48) - 2 = 142 and 48 + 5 = 53.
- Their average is: (142 + 53)/2 = 97.5.
- Correct Answer: Option 2: 97.5
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