Explanation:

- To solve this problem, we need to find the smallest number that, when divided by 5, 6, and 8, leaves a remainder of 3.

- This requires finding a number in the form of `L * lcm(5,6,8) + 3`.

- The least common multiple of 5, 6, and 8 is 120.

- Now, check options:

- Option 1 (243): 243 divided by 5, 6, and 8 leaves a remainder of 3.

- Option 2 (123): 123 divided by 5, 6, and 8 leaves remainders of 3, 3, 3, respectively.

- Option 3 (117): 117 divided by 5, 6, and 8 leaves remainders of 2, 3, and 5, respectively.

- Option 4 (792): 792 divided by 5, 6, and 8 leaves remainders of 2, 0, and 0, respectively.

- Therefore, the correct answer is Option 2 (123).

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