send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
80 liters of a mixture of alcohol and water contains 60% alcohol. If 'X' liters of water is added to this mixture, then the
percentage of alcohol in the new mixture becomes 40%. What is the value of X?
20
80
40
60
- You start with an 80-liter mixture containing 60% alcohol. This means there are 48 liters of alcohol (0.6 x 80 = 48).
- To find the new volume of the mixture after adding water, set the new alcohol percentage to 40%.
- The new mixture will have 48 liters of alcohol and total volume will now be 80 + X due to the added water.
- Set up the equation: (48 / (80 + X)) = 0.4, where 0.4 represents 40%.
- Solving for X gives: 48 = 0.4(80 + X), which simplifies to 48 = 32 + 0.4X, resulting in 16 = 0.4X.
- Solving for X gives X = 40.
- Correct answer is therefore Option 3: 40.
.
Report error
Access to prime resources