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The perimeter of a rectangle is 68 cm. If the area of the rectangle is 240 cm2, then what is the length of each of its diagonals?
25 cm
27 cm
26 cm
28 cm
- The perimeter of the rectangle is given as 68 cm.
- The formula for the perimeter is 2(l + w) = 68. Simplifying, l + w = 34.
- The area of the rectangle is given as 240 cm².
- The formula for the area is l × w = 240.
- You have two equations: l + w = 34 and l × w = 240.
- Solve these equations simultaneously to find l and w.
- From l + w = 34, express w = 34 - l.
- Substitute in the area equation: l(34 - l) = 240.
- This expands to a quadratic equation: l² - 34l + 240 = 0.
- Solving gives l = 20 cm or l = 12 cm, leading to w = 14 cm or w = 18 cm.
- Calculate the diagonal using the Pythagorean theorem: v(l² + w²).
- Using either dimension: v(20² + 14²) = v(400 + 196) = v596 ˜ 24.42 cm or v(18² + 12²) = v(324 + 144) = v468 ˜ 21.63 cm.
- None of the given options match exactly, but if approximating, none are close to 24.42 cm or 21.63 cm. Please check the problem or options again.
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