Explanation:

- A rhombus has all sides of equal length and its diagonals intersect at right angles.

- Given: Side = 10 cm, one diagonal (d1) = 16 cm.

- Let the other diagonal be $d2$.

- Diagonals bisect each other, forming two right triangles.

- Using the Pythagorean theorem: ${10}^2=(8{)}^2+(d2/2{)}^2$.

- Solving gives $(d2/2{)}^2={10}^2-8^2=36$.

- So, $d2/2=6$ cm, hence $d2=12$ cm.

- Area of a rhombus is $\frac{1}{2}\times d1\times d2$.

- Thus, area = $\frac{1}{2}\times 16\times 12=96$ cm${}^2$.

Correct Answer: 96 cm${}^2$