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The sum of two numbers is 2000 and their L.C.M. is 21879. The two numbers are ?
1993, 7
1991, 9
1989, 11
1987, 13
Let the numbers be x and (2000 - x). Then, their L.C.M. = x (2000 - x). So, x (2000 - x) = 21879 => x2 - 2000x + 21879 = 0. => (x - 1989) (x - 11) = 0, => x = 1989 or x = 11. Hence, the numbers are 1989 and 11.
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