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If 9 men and 12 boys can do a piece of work in 4 days and 4 men and 16 boys can do the same piece of work in 6 days, how long will 6 men and 24 boys take to complete the same work?
5 days
2 days
1 day
4 days
From the information given for the first two instances, (9M + 12B) x 4 = (4M + 16B)x 6 36M + 48B = 24M + 96B 36M - 24M = 96B - 48B 12M = 48B M = 48/12 B = 4B Now substitute this value for Boys in each instances, let’s calculate the total units of work in terms of Men (9 M + 12 B) x 4 = (9M + 3 M) x 4 = 48 M . So the total units of work done is 48. Now getting to the final instance, 6M + 24B = 6M + 24/4M = 12M. That means it is the same as the first case. So number of days required is 48/12 = 4
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