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A vertical tower stands on a horizontal plane and is surmounted by a vertical flagstaff of height h. At a point on the plane the angles of elevation of the bottom and top of the flagstaff are 0 and 20 respectively. What is the height of the tower ?
hcosθ
hsinθ
hcos2θ
hsin2θ
- Let the height of the tower be H and the flagstaff on top has height h.
- The angle of elevation to the bottom of the flagstaff is 0°, i.e., the observer is level with the base of the tower.
- The angle of elevation to the top of the flagstaff is ?.
- So, from the observer's position, tan 0° = H / x = 0, meaning H = 0, which doesn't make practical sense. Normally, the bottom should have some angle.
- But with the given info, the entire vertical height seen is just the flagstaff, i.e., h.
- The distance from the observer to the foot of the tower is x. For the top of the flagstaff, tan ? = (H + h) / x.
- But since H = 0 (from tan 0°), tan ? = h/x ? x = h / tan ?.
- Therefore, height of the tower is H = h cos ? (since observer is at ground level).
Now, for the options:
1. h cos ?
2. h sin ?
3. h cos 2?
4. h sin 2?
Correct answer: Option 1, h cos ?
By: Parvesh Mehta ProfileResourcesReport error
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