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A beaker contains a mixture of two liquids X and Y in the ratio 5 : 3. When 6 litres of the mixture is drawn off and then replaced
with Y, the ratio of X and Y becomes 5 : 7.
How many litres of liquid X was contained in the beaker initially?
18.25
22.5
11.25
15.5
Let's analyze the problem to find out how many litres of liquid X was initially in the beaker:
- The initial ratio of X to Y is 5:3. Let's say the initial quantities of X and Y are 5k and 3k litres, respectively.
- A total of 6 litres of the mixture is drawn off, which will contain 6 * (5/8) = 3.75 litres of X and 6 * (3/8) = 2.25 litres of Y since they are in the ratio 5:3.
- The new quantity of X is 5k - 3.75.
- The new quantity of Y becomes 3k - 2.25 + 6 after adding 6 litres of Y.
- The new ratio is given as 5:7, leading to the equation (5k - 3.75) / (3k + 3.75) = 5 / 7.
Solving this equation for k gives us 2.25.
- To find the initial quantity of X: 5k = 5 * 2.25 = 11.25 litres.
- Correct answer is: Option 3: 11.25 litres
.
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