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A work is done by 30 workers not all of them have the same capacity to work. Every day exactly 2 workers, do the work with no pair of workers working together twice. Even after all possible pairs have worked once, all the workers together works for six more days to finish the work. Find the number of days in which all the workers together will finish the work?
22 days
20 days
24 days
35 days
Explanation : 30 workers work in pairs, with no same pair of workers working together twice 29[1/w1 + 1/w2 ….. + 1/w30] + 6[1/w1 + 1/w2 ….. + 1/w30] = 1 [1/w1 + 1/w2 ….. + 1/w30] = 1/35 35 days.
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