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A is two years younger than B. If seven years back, five-sixth of A's age exceeded three-tenth of B's age by nine years, what is B's present age?
25 years
27 years
28 years
None of these
Let the present ages of A and B are A and B respectively. So we can say B – A = 2 ----- eq1 Also 5/6 (A-7) – 3/10 (B - 7) = 9 ----- eq2 By solving eq1 and eq2 :- B = 27 years
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