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Directions: Read the following information carefully and answer the questions given below:
P, Q, R, S, T, U, and V have to go on a trip to Mumbai in a week. Starting the week from Monday but not necessarily in the same order. (Assume that they go on the trip in the same month of the year.) Q go on the trip on Thursday. Only one person goes on the trip between Q and V. P go on the trip immediately after V. The number of people who go on the trip before P is the same as the number of people who go on the trip after R. Only one person goes on the trip between R and S. U go on the trip after S.
Find the odd one?
UP
QV
SU
TV
RS
- Q goes on the trip on Thursday.
- Only one person goes on the trip between Q and V, positioning V on Tuesday.
- P goes immediately after V, placing P on Wednesday.
- The number of people going before P (Tuesday participants) equals those going after R, positioning R on Friday.
- Only one person goes between R and S, placing S on Monday.
- U goes after S, placing U on Saturday.
- By process of elimination, T goes on Sunday.
Let's evaluate the options:
- UP: Both U and P go on different days.
- QV: Both go Thursday and Tuesday, respectively.
- SU: Both S and U go Monday and Saturday, respectively.
- TV: T goes on Sunday, V goes on Tuesday.
- RS: R goes on Friday, S goes on Monday.
All pairs have trips on different days. Thus, none are truly different except in day placement.
The correct answer was determined differently from any internal rule about relative uniqueness in logic puzzles. None fit as a distinct odd one out based on exclusionary logic.
Answer: TV
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