Sun	Mon	Tue	Wed	Thu	Fri	Sat
23	24	25	26	27	28	1
2	3	4	5	6	7	8
9	10	11	12	13	14	15
16	17	18	19	20	21	22
23	24	25	26	27	28	29
30	31	1	2	3	4	5

Back to Main Page

Multiple Choice Questions

N is the greatest number which divides 1305 4665 and 6905 and gives the same remainder in each case ...........

Quantitative Aptitude (CPO) LCM, HCF

N is the greatest number which divides 1305, 4665 and 6905 and gives the same remainder in each case. What is the sum of the digits in N?

छोटे Courses बड़े Results

Master LCM, HCF

Prepare through Micro-courses

Try Now

Explanation:

If the remainder is same in each case and remainder is not given,

HCF of the differences of the numbers is the required greatest number
6905 – 1305 = 5600
6905 – 4665 = 2240
4665 – 1305 = 3360
Hence, the greatest number which divides 1305, 4665 and 6905 and gives the same remainder, N
= HCF of 5600, 2240, 3360
= 1120
Sum of digits in N
= Sum of digits in 1120
= 1 + 1 + 2 + 0 = 4

Hence, option 1 is the correct answer.

Report error

Submit Error