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Direction: Study the following Table and answer the questions that follow:
Bhuvan and Kachara started doing the work. After working for 5 Days they left the work for Tipu. He completed his part of work. Now the remaining work was completed by Arjan in 7.5 days. In how many days can Arjan complete whole work?
20
4
30
16
15
Explanation – Bhuvan: 15% = 6 days 100% = (6/15) × 100 = 40 days Kachara: 15% = 3 days 100% = (3/15) × 100 = 20 days Tipu: 25% = 4 days 100% = 16 days Now we can find the Total work by taking LCM of number of days taken by Bhuvan, Kachara and Tipu LCM ( 40 , 20, 16) = 80 unit (Total work) Now we can find efficiency of each persons. Bhuvan = 2 unit Kachra = 4 unit In 1 days Bhuvan and Kachara complete 6 unit of work so in 5 day = 6 × 5 = 30 unit Tipu completes 25% of total work = 80 × 25/100 = 20 unit Remaining work = 80 – (30+20) = 30 unit Arjan completes it in 7.5 days, Efficiency of Arjan = 30 /7.5 = 4 unit ( in 1 day) Arjan can complete total work in, = 80/4 = 20 days
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