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The average age of boys in the class is twice the number of girls in the class. The ratio of boys and girls in the class of 50 is 4:1. Find The total of the ages of the boys in the class
400
600
800
1000
Number of students in the class = 50
Ratio of Boys : Girls = 4 : 1
Let x be the constant ratio
Ratio of Boys : Girls = 4x : 1x
Sum of their age is 50
4x + 1x = 50
5x = 50 = x = 10 Find the number of boys and girls:
girls = x = 10
boys = 4x = 4(10) = 40 Find the average of the boys' age:
average = 2 x number of girls = 2(10) = 20 Find the sum of the boy's age:
Average of the age of the 40 boys = 20
sum of the age of the 40 boys = 20 x 40 = 800 years
Hence, option 3 is the correct answer.
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