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M can do a piece of work in 10 days working 10 hours a day. The work is started by M and on the second day one man whose capacity to do the work is twice that of M, joined. On the third day another man whose capacity is thrice that of M, joined and the process continues till the work is completed. In how many days will the work be completed, if everyone works for five hours a day?
4
6
7
3
Solution: M total work 10*10=100 1st day =5hrs 2nd day =10+5=15 3rd day =15+10+5=30 4th day =20+15+10+5=50 Total (5+15+30+50) = 100 So 4th day they completed the work.
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Goliath
Why are we adding 20 on the 4th day??
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