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Find the number of factors of the two digit number.
Statement I: The two-digit number is 27 more than the two-digit number obtained by reversing the digits of the number.
Statement II: The number is multiple of 9.
Both are necessary
From I: Let the required number be (10x+y). Now, 10x + y = 10y + x + 27 => (x – y) = 3 So, the possible values of x and y are 96,85,74,63,52 and 41. We cannot find an unique solution. So, this statement is not alone to solve the question. From II: Two-digit numbers which are multiple of 9 = 18,27,36,45,54,63,72,81,90,99 We cannot find unique solution. So, this statement alone is not sufficient. Combining both the equations. Let the required number be (10x+y). 10x + y = 10y + x + 27 => (x – y) = 3 So, the possible values of x and y are 96,85,74,63,52 and 41. Two-digit numbers which are multiple of 9 = 18,27,36,45,54,63,72,81,90,99. So, 63 is the required two-digit number. So, the factors of 63 are 1,3,7,9 21,63. Both are necessary to answer.
Hence, option 5 is the correct answer.
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