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P can do a task in 30 days, Q is 50% more efficient than P, R can do the same work in 10days less than Q if R and Q start task together and after X days they left the task and P completed the remaining task in ( X + 8 ) days. then find the value of X ?
2
4
5
8
6
- P completes the task in 30 days.
- Thus, P's daily work rate = 1/30 of the work.
- Q is 50% more efficient than P.
- So, Q's work rate = 1.5 * (1/30) = 1/20 of the work per day.
- R completes the task in 10 days less than Q.
- Therefore, R's task completion time = 10 days, and R's work rate = 1/10 of the work per day.
- Q and R work together, so their combined daily work rate is 1/20 + 1/10 = 3/20 of the work.
- Together, they work for X days, completing 3X/20 of the task.
- The remaining work (1 - 3X/20) is completed by P in X + 8 days.
- So, the remaining work done by P is (1 - 3X/20) = (X + 8) * (1/30).
Calculate X:
1−3X20=X+830
Let's solve for X:
30−90X20=X+8
600−90X=20X+160
600−160=20X+90X
440=110X
X=4
- The correct option is 4.
- Option:2, 4
-
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