Sun	Mon	Tue	Wed	Thu	Fri	Sat
29	30	1	2	3	4	5
6	7	8	9	10	11	12
13	14	15	16	17	18	19
20	21	22	23	24	25	26
27	28	29	30	31	1	2
3	4	5	6	7	8	9

Back to Main Page

Web Notes

Ratio and Proportion (DI)

Quantitative Aptitude(IBPS PO) Ratio, Proportion

Data Interpretation( Ratio and Proportion)

Data Interpretation is an essential part of Quantitative Aptitude Section of every Banking Examination. 10-15 questions in every Preliminary Banking Examination are from Data Interpretation.So, we hope, now you understand how important it is for a banking aspirant to practice Data Interpretation.

The DI’s generally asked are Tabular DI’s, Bar Graphs, Line Graphs, Cumulative Bar Graph, Pie Chart, Radar Graph, and Missing DI. The new pattern DI’s that are now being asked in the exams can be based on any miscellaneous topics like Time and Work, Pipes and Cisterns, etc. So one cannot expect the old pattern questions only that used to be based on simple Profit and Loss, Percentage or Ratio and Proportion Concept. Any of the old or new pattern DI’s can be asked in the upcoming banking examinations.

Here are some example of DI based on Ratio and Proportion:

Direction (1-5 ): Study the following table chart carefully and answer the questions given beside.
The data related to three core branches of engineering in five different IITs are given in the table.

BRANCHES	Number of students in Mechanical Engineering	Ratio of students in Civil to Mechanical Engineering	Ratio of students in Electrical to Civil Engineering
IIT Delhi	1080	17 : 20	32 : 27
IIT Bombay	1420	11 : 10	19 : 22
IIT Kharagpur	1640	36 : 41	23 : 18
IIT Kanpur	1260	31 : 28	49 : 45
IIT Madras	1584	13 : 16	34 : 39

Question 1:

Find the difference between the number of students of Electrical engineering of IIT Delhi to that of IIT Bombay.

(A) 311 (B) 221 (C) 261 (D) 321 (E) 291

Solution:

Total number of students in Electrical engineering in IIT Delhi

$=\frac{32}{27}\times \frac{17}{20}\times 1080=1088$

Total number of students in Electrical engineering in IIT Bombay

$=\frac{19}{22}\times \frac{11}{10}\times 1420=1349$

Required difference = 1349 – 1088 = 261
Hence, option C is correct.

Question 2:

35% and 20% of total students of Civil engineering of IIT Kharagpur are studying in 1st year and in 2nd year respectively while the ratio of number of students studying in 1st year, 2nd year, 3rd year, and 4th year in Civil Engineering in IIT Kanpur is 7:9:8:7 respectively. The total number of students studying in 1st year and in 2nd year together in Civil in IIT Kanpur is approximately what percent of the total number of students studying in 1st year and in 2nd year together in Civil in IIT Kharagpur?

(A) 86% (B) 91% (C)96% (D)82% (E)76%

Solution:Total number of students studying in 1st year in Civil in IIT Kharagpur
35% of 36/41 x 1640=504

Total number of students studying in 2nd year in Civil in IIT Kharagpur

=20% of 36/41 x 1640=288
Total number of students studying in 1st year in Civil in IIT Kanpur

$=\frac{7}{31}\times \frac{31}{28}\times 1260=315$

Total number of students studying in 2nd year in Civil in IIT Kanpur

$=\frac{9}{31}\times \frac{31}{28}\times 1260=405$

$Reqd%=\frac{315+405}{504 + 288}\times100 =91%$

Hence, option B is correct

Qustion 3:

If the ratio of the number of students in Electronics to Mechanical in IIT Bombay and IIT Kanpur is 4:5 and 71:70 respectively, then find the ratio of the number of students in Electronics in IIT Bombay to that in IIT Kanpur.

(A)8 : 9 (B)7 : 9 (c)5 : 6 (D)6 : 5 (E)9 : 8

Solution:

Total number of students in Electronics in IIT Bombay

=4/5 x 1420 =1136

Total number of students in Electronics in IIT Kanpur

=71/70 x 1260=1278

Required ratio = 8 : 9

Hence, option A is correct.

Question 4:

The total number of students of Civil Engineering of all the given colleges is approximately what percent of the total number of students of Mechanical Engineering of all the given colleges?

(A)91% (B)95% (C)84% (D)112% (E)103%

Solution:

Q.Number of students in civil in IIT Delhi
=17/20 x 1080=918

Number of students in civil in IIT Bombay

=11/10 x 1420=1562
Number of students in civil in IIT Kharagpur

=36/41 x 1640=1440

Number of students in civil in IIT Kanpur

= 31/28 x 1260= 1395
Number of students in civil in IIT Madras

=13/16 x 1584=1287

Total number of students in civil in all five colleges = 918 + 1562 + 1440 + 1395 + 1287 = 6602

Total number of students in Mechanical in all five colleges = 1080 + 1420 + 1640 + 1260 + 1584 = 6984

Reqd. % =6602/6984 x 100 =95%

Hence, option B is correct.

Question 5:

The total number of students in Computer Science in IIT Kharagpur, IIT Kanpur, and IIT Madras together is 286 more than the total number of students in Electrical in the same colleges together. Find the total number of students in Computer Science in IIT Kharagpur, IIT Kanpur, and IIT Madras together.

(A)4197 (B)5257 (C)4357 (D)4767 (E)4987

Solution:

Total number of students in Electrical in IIT Kharagpur

$=\frac{36}{41}\times \frac{23}{18}\times 1640=1840$

Total number of students in Electrical in IIT Kanpur

$=\frac{31}{28}\times \frac{49}{45}\times 1260=1519$
Total number of students in Electrical in IIT Madras

$=\frac{13}{16}\times \frac{34}{39}\times 1570=1122$

Total number students in Computer Science in IIT Kharagpur, IIT Kanpur, and IIT Madras together

= 1840 + 1519 + 1122 + 286 = 4767

Hence, option D is correct.

छोटे Courses बड़े Results

Master Ratio, Proportion

Prepare through Micro-courses