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A man invested Rs. 26000 in 5% stock at 104. He sold the stock when the price rose to Rs. 120 and invested the sale proceeds in 6% stock. By doing this his income increased by Rs. 2500. At what price did he purchase the second stock?
Rs. 22
Rs. 48
Rs. 64
Rs. 80
Assuming that face value of the first stock = Rs.100 as it is not given in the question Since it is a 5% stock, we can take the dividend per stock = Rs.5 Market Value of the first stock = Rs.104 Investment on the first stock = Rs.26000 Number of stocks purchases = 26000/104 = 250 His total income from all these stocks = Rs.250 × 5 = Rs.1250 He sells each of this stock at Rs.120 ie, amount he earns = Rs.120 × 250 = Rs.30000 He invest this Rs.30000 in 6% stock (here also face value is not given and hence take it as Rs.100) His new income = Rs.(1250 + 2500) = Rs.3750 ie, By Rs.30000 of investment , he earns an income of Rs.3750 To get an income of Rs.6, investment needed = 3000 x 6 /3750 = 48 rs.
Hence, option 2 is the correct answer.
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