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Study the following information and answer the questions that follow: In a boating competition there are 3 boats X, Y and Z taking in the race. The river in which the race is to be held is divided into three equal parts AB, BC and CD. To complete the race a boast must travel from A to D downstream and back from D to A upstream. The speed of stream in part BC is 50% of the speed of stream in part AB, while the speed of stream in part CD is 150% of the speed of the stream in part AB. Speed of boat X in still water= 6 kmph; Speed of boat Y in still water= 5 kmph Speed of boat Z in still water= 8 kmph
X, Y and Z starts the race from position A. What distance more would boat Z have travelled than boat Y at the time when boat Y reaches point B? (Distance AD= 210 km and speed is stream in region BC is 1 kmph)
20 km
25 km
27 km
28 km
Time taken by boat Y to reach B= (Distance AB)/ downstream speed for Y= 70/(5+2)=10 hours Time taken by Z to travelled AB= 70/ (8+2)=7 hours In this extra 10-7 hours=3 hours; Z is in region BC where speed of stream is 1 kmph So distance travelled by Z in region BC in 3 hours= 3* (8+1)= 27 km So Z is 27 km ahead of Y when Y reaches B
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