Sun	Mon	Tue	Wed	Thu	Fri	Sat
23	24	25	26	27	28	1
2	3	4	5	6	7	8
9	10	11	12	13	14	15
16	17	18	19	20	21	22
23	24	25	26	27	28	29
30	31	1	2	3	4	5

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Multiple Choice Questions

A man lsquo A rsquo can do a piece of work in 10 days man lsquo B rsquo can do the same piece of wor...........

Quantitative Aptitude (PCS) Time and work

A man ‘A’ can do a piece of work in 10 days, man ‘B’ can do the same piece of work in 12 days while man ‘C’ can do it in 15 days. They started work together but after 2 days ‘A’ left the work and the remaining work was completed by ‘B’ and ‘C’ together. Find in how many days will the work be completed.

5 days

7 days

2 1/6 days

3 1/3 days

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Explanation:

Solution:
A…..10 6unit
B……12 Lcm=60 5unit
C…….15 4unit
Work of all 3 per day is 15 units (6+5+4)
All 3 worked for 2 days. So 2 days work is 2*15=30units.
Remaining (60-30)=30unit
That work done by B and C their per day work unit (5+4)=9unit
Remaining work done by B and C is 30/9=3 1/3 days.

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