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If x = 2015, y = 2014 and z = 2013, then value of x2 + y2 + z2 – xy – yz – zx is
3
4
6
2
x – y = 2015 – 2014 = 1 y – z = 2014 – 2013 = 1 z – x = 2013 – 2015 = –2 ∴ x2 + y2 + z2 – xy – yz – zx Numerator & denominator multiplied by 2, = 1/2(2x2 + 2y2 + 2z2 – 2xy – 2yz – 2zx) = 1/2(x2 + y2 – 2xy + y2 + z2 – 2yz + z2 + x2 – 2zx) = 1/2[(x– y)2 + (y – z)2 + (z – x)2] = 1/2[1 + 1 + 4] = 1/2 × 6 = 3
Guru Mayadhar Raut, who passed away recently was a famous ________________dancer.
Odissi
Bharatnatyam
Kuchipudi
Kathakal
Guru Mayadhar Raut, famous Odissi dancer passed away on February 22 in New Delhi. Guruji, as Mayadhar Raut was respectfully addressed by all, was born in the village of Kantapanhara in Cuttack district on July 6, 1930.
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