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10 men , 6 women and 9 boys were given a project of doing 2000 designs of a building in 5 days. All of them designed on the first day. On the second day 2 women and 3 boys are absent. On the third day , 3 men and and 5 boys are absent. If the ratio of the number ofdesigns done by them is in the ratio 3 : 2 : 1 respectively. Then find the number of designs designed by them on the second day (approx.)?
620
600
667
650
Solution: Let the ratio be 3x : 2x : 1x Designs of building on the first day = 10 * 3x + 6 * 2x + 9 * x = 51x On the second day = 10 * 3x + 4 * 2x + 6 *x = 44x On the third day = 7 *3x + 6 * 2x + 4 * x = 37x Now, 51x + 44x + 37x = 2000 => 132x = 2000 Therefore, 2000/132*44 = 666.66 = 667 (approx.)
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