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N is the greatest number which divides 1305, 4665 and 6905 and gives the same remainder in each case. What is the sum of the digits in N?
4
3
6
5
If the remainder is same in each case and remainder is not given,
HCF of the differences of the numbers is the required greatest number 6905 – 1305 = 5600 6905 – 4665 = 2240 4665 – 1305 = 3360 Hence, the greatest number which divides 1305, 4665 and 6905 and gives the same remainder, N = HCF of 5600, 2240, 3360 = 1120 Sum of digits in N = Sum of digits in 1120 = 1 + 1 + 2 + 0 = 4
Hence, option 1 is the correct answer.
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