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hemispherical tank fill of water is emptied by a pipe at the rate of 15.4 litres per second. How much time (in hours) will it take to empty 3/4 part of the tank, if the internal radius of the tank is 7 m?
175/18 hours
125/21 hours
145/12 hours
150/31 hours
Answer not known
- Calculate the volume of the tank:
- The tank is hemispherical with a radius of 7 meters.
- Volume of a hemisphere = \((2/3) \times \pi \times r^3\).
- Plug in the radius: \((2/3) \times \pi \times 7^3 \approx 718.4 \, \text{m}^3\).
- Convert the volume to liters:
- 1 m³ = 1000 liters, so 718.4 m³ = 718,400 liters.
- Calculate 3/4 of the volume:
- \((3/4) \times 718,400 \approx 538,800 \, \text{liters}\).
- Determine time to empty 538,800 liters at 15.4 liters/sec:
- Time = Total volume / Rate = 538,800 / 15.4 seconds.
- Time ˜ 35,000 seconds.
- Convert seconds to hours:
- 1 hour = 3600 seconds.
- Time = 35,000 / 3600 ˜ 350/36 ˜ 175/18 hours.
- Check options for correct match:
- ?? Option 1: 175/18 hours is the match.
.
By: Parvesh Mehta ProfileResourcesReport error
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