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Two years ago, the age of A was three times the age of B. If B is currently 9 years old, then after how many years, the age of A will be double of the age of B?
3 years
4 years
5 years
- Two years ago, B was 7 years old (since B is currently 9 years old).
- At that time, A was three times B's age, making A 21 (3 times 7).
- Currently, A is 23 years old (21 + 2 years).
- The goal is to find when A's age will be double B's age.
- Suppose this occurs in x years. The equations are:
- A's future age = 23 + x
- B's future age = 9 + x
- The condition is: 23 + x = 2(9 + x).
- Solving:
- 23 + x = 18 + 2x
- 23 - 18 = 2x - x
- 5 = x
- After 5 years, A's age will be double B's age.
- Correct Answer: Option 4, 5 years.
By: Parvesh Mehta ProfileResourcesReport error
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