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Which one of the following is the greatest number by which the product of three consecutive even numbers would be exactly divisible ?
12
24
48
64
Let’s break it down step by step:
- When you multiply three consecutive even numbers—for example, 2, 4, 6—you get 2 × 4 × 6 = 48.
- Any set can be written as n, n+2, n+4 (where n is an even number). Their product: n × (n+2) × (n+4).
- All three are even, so the product will always be divisible by 8 (since at least one is divisible by 4 and another by 2).
- Let's check options:
- 12: Always divides, but not the largest.
- 24: Also always divides.
- 48: For three consecutive even numbers, one is a multiple of 4, one is a multiple of 2 (other than first), and one could be a multiple of 8 or not. But not always, since among any three consecutive even numbers, at least one is divisible by 4, but NOT necessarily by 8 (e.g., 2, 4, 6).
- 64: Too large (since 2, 4, 6 give 48).
- For 2, 4, 6 the product is 48, which is not divisible by 64 but is by 48.
Option 3: 48 is correct; the product is always divisible by 48.
By: Parvesh Mehta ProfileResourcesReport error
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